Statistics Solution for this Question
Factory A | Factory B | |
---|---|---|
Number of Employees | – | – |
Average Wages (₹) (𝜇) | 1200 | 100 |
Variance (σ²) | 81 | 256 |
(a) In which factory is there greater variation in the distribution of wages per employee?
We calculate the Coefficient of Variation (C.V.) using:
Cv = (σ / μ) × 100
Factory A:
μA = 1200
σ²A = 81 → σA = √81 = 9
Cv(A) = (9 / 1200) × 100 = 0.75%
Factory B:
μB = 100
σ²B = 256 → σB = √256 = 16
Cv(B) = (16 / 100) × 100 = 16%
✅ Conclusion (a):
Factory B has a greater variation in wages because its C.V. (16%) is greater than Factory A (0.75%).
Factory B has a greater variation in wages because its C.V. (16%) is greater than Factory A (0.75%).
(b) Suppose in factory B, the wages of an employee were wrongly noted as ₹900 instead of ₹910.
To correct the variance, use the formula:
σnew² = σ² + [(xtrue - μ)² - (xwrong - μ)²] / n
xtrue = 910
xwrong = 900
μ = 100
σ² = 256
n = 100
σnew² = 256 + [(910 - 100)² - (900 - 100)²] / 100
= 256 + (656100 - 640000) / 100
= 256 + 16100 / 100
= 256 + 161
= 417
✅ Conclusion (b):
Corrected Variance (σ²) = 417
Corrected Variance (σ²) = 417
Note:
- μ = Mean
- σ² = Variance
- σ = Standard Deviation
- Cv = Coefficient of Variation
- μ = Mean
- σ² = Variance
- σ = Standard Deviation
- Cv = Coefficient of Variation
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