Statistics Q6 Solution

Statistics Solution for this Question

Factory A Factory B
Number of Employees
Average Wages (₹) (ЁЭЬЗ) 1200 100
Variance (╧Г²) 81 256

(a) In which factory is there greater variation in the distribution of wages per employee?

We calculate the Coefficient of Variation (C.V.) using:

Cv = (╧Г / ╬╝) × 100

Factory A:

╬╝A = 1200
╧Г²A = 81 → ╧ГA = √81 = 9

Cv(A) = (9 / 1200) × 100 = 0.75%

Factory B:

╬╝B = 100
╧Г²B = 256 → ╧ГB = √256 = 16

Cv(B) = (16 / 100) × 100 = 16%
Conclusion (a):
Factory B has a greater variation in wages because its C.V. (16%) is greater than Factory A (0.75%).

(b) Suppose in factory B, the wages of an employee were wrongly noted as ₹900 instead of ₹910.

To correct the variance, use the formula:

╧Гnew² = ╧Г² + [(xtrue - ╬╝)² - (xwrong - ╬╝)²] / n

xtrue = 910
xwrong = 900
╬╝ = 100
╧Г² = 256
n = 100

╧Гnew² = 256 + [(910 - 100)² - (900 - 100)²] / 100
= 256 + (656100 - 640000) / 100
= 256 + 16100 / 100
= 256 + 161
= 417
Conclusion (b):
Corrected Variance (╧Г²) = 417
Note:
- ╬╝ = Mean
- ╧Г² = Variance
- ╧Г = Standard Deviation
- Cv = Coefficient of Variation
FF

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