Statistics Q6 Solution

Statistics Solution for this Question

Factory A Factory B
Number of Employees
Average Wages (₹) (𝜇) 1200 100
Variance (σ²) 81 256

(a) In which factory is there greater variation in the distribution of wages per employee?

We calculate the Coefficient of Variation (C.V.) using:

Cv = (σ / μ) × 100

Factory A:

μA = 1200
σ²A = 81 → σA = √81 = 9

Cv(A) = (9 / 1200) × 100 = 0.75%

Factory B:

μB = 100
σ²B = 256 → σB = √256 = 16

Cv(B) = (16 / 100) × 100 = 16%
Conclusion (a):
Factory B has a greater variation in wages because its C.V. (16%) is greater than Factory A (0.75%).

(b) Suppose in factory B, the wages of an employee were wrongly noted as ₹900 instead of ₹910.

To correct the variance, use the formula:

σnew² = σ² + [(xtrue - μ)² - (xwrong - μ)²] / n

xtrue = 910
xwrong = 900
μ = 100
σ² = 256
n = 100

σnew² = 256 + [(910 - 100)² - (900 - 100)²] / 100
= 256 + (656100 - 640000) / 100
= 256 + 16100 / 100
= 256 + 161
= 417
Conclusion (b):
Corrected Variance (σ²) = 417
Note:
- μ = Mean
- σ² = Variance
- σ = Standard Deviation
- Cv = Coefficient of Variation
FF

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